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If i=sqrt-1, then 4+5(-1/2+(isqrt3)/2)^3...

If `i=sqrt-1,` then `4+5(-1/2+(isqrt3)/2)^334+3(-1/2+(isqrt3)/2)^365` is equal to (1) `1-isqrt3` (2) `-1+isqrt3` (3) `isqrt3` (4) `-isqrt3`

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