10ab+4a+5b+2

Find the value of the expression 3ab - 4a + 5 ,if a=4 and b = 2 .

Simplify (5a-2b) (25a^(2)+10ab+4b^(2)_) -(2a+5b) (4a^(2)-10ab+25b^(2)).

Subtract 4a - 7ab + 3b + 12 from 12a - 9ab + 5b -3

Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3

Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3

Subtract : 2ab ^(2)c ^(2) + 4a ^(2) b ^(2) c - 5 a ^(2) b ^(2) from - 10 a ^(2) b ^(2) c ^(2) + 4 ab ^(2) c ^(2) + 2 a ^(2) bc ^(2)

The reaction of A_(2) and B_(2) follows the equation A_(2)(g)+B_(2)(g)to2AB(g) The following data were observed {:(,[A_(2)]_(0),[B_(2)]_(0),"Initial rate of appearance of AB(g)(in" Ms^(-1)),(,0.10,0.10,2.5xx10^(-4)),(,0.20,0.10,5xx10^(-4)),(,0.20,0.20,10xx10^(-4)):} The value of rate constatnt for the above reaction is : a) 2.5xx10^(-4) b) 2.5xx10^(-2) c) 1.25xx10^(-2) d) None of these

Divide : 4a^(2) + 12ab + 9b^(2) - 25c^(2) by 2a + 3b + 5c

Factorise the using the identity a ^(2) - 2 ab + b ^(2) = (a -b) ^(2). 4a ^(2) - 4 ab + b ^(2)

If (5a - 3b) : (4a - 2b) = 2:3, then a:b is equal to: यदि (5a - 3b) : (4a - 2b) = 2:3 है, तो a : b का मान क्या होगा ?