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" (iv) "(3e^(2x))/(1+e^(4x))...

" (iv) "(3e^(2x))/(1+e^(4x))

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The solution of the differential equation (dy)/(dx) = (3e^(2x) + 3e^(4x) )/( e^(x) + e^(-x) ) is a) y= e^(3x) + C b) y=2e^(2x) + C c) y= e^(x) + C d) y= e^(4x) + C

If y=tan^(-1)((e^(2x)+1)/(e^(2x)-1)) , prove that : dy/dx=-(2e^(2x))/(1+e^(4x)) .

int(3e^(x)-4)/(e^(x)+1)dx=

Integrate the following with respect to x. (i) (e^(2x) - 1)/(e^x) " " (ii) e^(3x)(e^(2x - 1)) .

int(e^(4x)-1)/(e^(2x))dx

int (e ^ (3x) + e ^ (x)) / (e ^ (4x) -e ^ (2x) +1) dx

Evaluate : int (2e^(4x)-3e^(2x)+4)/(e^(3x))dx

Let a=int_0^(log2) (2e^(3x)+e^(2x)-1)/(e^(3x)+e^(2x)-e^x+1)dx , then 4e^a =

Let a=int_0^(log2) (2e^(3x)+e^(2x)-1)/(e^(3x)+e^(2x)-e^x+1)dx , then 4e^a =