[" If the system of linear equations "],[x+y+3z=0],[x+3y+k^(2)z=0],[3x+y+3z=0]

What should be the value of k so that the system of linear equations x - y + 2z = 0, kx - y + z = 0, 3x + y - 3z = 0 does not possess a unique solution ?

What should be the value of k so that the system of linear equations x - y + 2z = 0, kx - y + z = 0, 3x + y - 3z = 0 does not possess a unique solution ?

If x =a, y=b, z=c is a solution of the system of linear equations x + 8y + 7z =0, 9 x + 2y + 3z =0, x + y+z=0 such that point (a,b,c ) lies on the plane x + 2y + z=6, then 2a+ b+c equals

If x =a, y=b, z=c is a solution of the system of linear equations x + 8y + 7z =0, 9 x + 2y + 3z =0, x + y+z=0 such that point (a,b,c ) lies on the plane x + 2y + z=6, then 2a+ b+c equals

If the system of linear equations x+ky+3z=0 3x+ky-2z=0 2x+4y-3z=0 has a non-zero solution (x,y,z) then (xz)/(y^2) is equal to

If the system of linear equations x+ky+3z=0; 3x+ky-2z=0; 2x+4y-3z=0 has a non-zero solution (x,y,z) then (xz)/(y^2) is equal to

If the system of linear equations x+ky+3z=0 3x+ky-2z=0 2x+4y-3z=0 has a non-zero solution (x,y,z) then (xz)/(y^2) is equal to

If x=a,y=b,z=c is a solution of the system of linear equations x+8y+7z=0,9x+2y+3z=0,x+y+z=0 such that the point (a,b,c) lies on the plane x+2y+z=6, then 2a+b+c equal to

Solve the following system of linear equations. x+y+z=3 , y-z=0 , 2x-y=1