[" 19) "x+(6)/(y)=6],[" i "3x-(8)/(y)=5quad (y!=0)]

x+(6)/(y)=6,3x-(8)/(y)=5 then y=………

x + ( 6) /( y ) = 6, 3x - ( 8)/( y) = 5 ( y ne 0 )

Solvex + (6) / (y) = 6.3x- (8) / (y) = 5

solve for x and y, x+ (6/y)=6,3x-(8/y)=5

Solve each pair of equation by using the substitution method. x+(6)/(y)=6 and 3x-(8)/(y)=5 .

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

I. (3x-2)//y=(3x+6)//(y+16) II. (x+2)//(y+4) = (x+5)//(Y+10)

The circles x^(2)+y^(2)-6x-8y=0 and x^(2)+y^(2)-6x+8=0 are

The equation of the tangent to the curve x^2-2xy+y^2+2x+y-6=0 at (2,2) is a) 2x+y-6=0 b) 2y+x-6=0 c) x+3y-8=0 d) 3x+y-8=0