The angular momentum of a particle changes from `4kg m^(2)s^(-1)` to `8kg m^(2)s^(-1)` is `2` seconds. Calcualte the torque acting on the particle

If there a change in the angular momentum of a body from "5 kg-m"^(2)//s to "8 kg-m"^(2)//s in 4 seconds, then the torque acting on the body is

Momentum of an object changes from 100 kg m/s to 200 kg m/s in 2 seconds. What is the force applied to it?

The angular momentum of a flywheel having a moment of inertia of 0.4 kg m^(2) decreases from 30 to 20 kg m^(2)//s in a period of 2 second. The average torque acting on the flywheel during this period is :

The uncertainty in the momentum of a particle is 6.0 xx 10^(-2) kg m s^(-1) .Calculate the uncertainty in the position

The uncertainty in the momentum of a particle is 6.0 xx 10^(-2) kg m s^(-1) .Calculate the uncertainty in the position

A particle is moving on a straight line x + y = 2. Its angular momentum about origin is L = 3t + 2 (kg m^2s^(-1) ). Find the force acting on the particle at t = 2 s. (x and y are in metre)

The momentum P ( in kg ms^(-1) ) of a particle is varying with time t ( in second ) as p=2+ 3t^(2) . The force acting on the particle at t=3s will be

The momentum P ( in kg ms^(-1) ) of a particle is varying with time t ( in second ) as p=2+ 3t^(2) . The force acting on the particle at t=3s will be