फलन t सेल्सियस तापमान का फारेनहाइट तापमान में प्रतिचित्रण करता है , जो `t(C )=(9C)/(5)+32` द्वारा परिभाषित है निम्नलिखित को ज्ञात कीजिए :
`(i) t(0) (ii) t(28) (iii) t(-10) (iv) C ` का मान , जब t(C )=212.

If t(C)=(9C)/5+32 write the value of t(28)

The function 't', which maps temperature in Clesius into temperature Fahrenheit is defined by t(C )= (9C)/(5) + 32 . Find : (i) t(0) (ii) t(28) (iii) t(-10) (iv) the value of c when t (c ) = 212.

The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/(5)+32 Find (i) t(0) (ii) t(28) (iii) t(-10) (iv) The value of C, when t(C)=212.

The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/(5)+32 Find (i) t(0) (ii) t(28) (iii) t(-10) (iv) The value of C, when t(C)=212.

The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/(5)+32 Find (i) t(0) (ii) t(28) (iii) t(-10) (iv) The value of C, when t(C)=212.

The function 't' which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/(5)+32 Find (i) t(0) (ii) t(28) (iii) t(-10) (iv) The value of C, when t(C)=212.

The function t which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/5+32 .Find (i) t (0) (ii) t(28) (iii) t(-10) (iv) The value of C, when t(C) = 212 .

The function t which maps temperature in degree Celsius into temperature in degree Fahrenheit is defined by t(C)=(9C)/5+32 . Find (i) t (0) (ii) t(28) (iii) t(" "10) (iv) The value of C, when t(C)" "=" "212 .