`CH_(3)CH(OH)COOH` molecule shows:

Lactic acid, CH_3CH(OH)COOH molecule shows:

The type of isomerism shown by : CH_(3)CH(OH)COOH is :

(A): CH_(3)CH(OH)COOH is optically active (R) : CH_(3)CH(OH)COOH do not possess any element of symmetry. The correct answer is

CH_(3)CH(OH)CH_(2)CH_(2)COOH

IUPAc name of CH_(3)CH(OH)COOH is

The intermediate formed when CH_(3)COOH react with CH_(3)CH_(2)OH in presence of HCl