If `bara` is perpendicular to `barb` and `barc` , then : `abs(baraxx(barbxxbarc))=`

If bara is perpendicular to barb and barc , abs(bara)=2,abs(barb)=3,abs(barc)=4 and mangle(barb,barc)=(2pi)/3, then : [barabarb barc] =

If bara is perpendicular to both barb and barc , absbara=2,absbarb=4,absbarc=6,(barb,barc)=(pi)/12 then find abs([bara,barb,barc])

bara is perpendicular to barb,barc . If abs(bara)=2,abs(barb)=3,abs(barc)=4(barb,barc)=(2pi)/3 then abs(barabarbbarc])=

If bara is perpendicular to barb and barc,|bara|=2,|barb|=3,|barc|=4 and the angle between barb and barc is (2pi)/(3) . then [bara" "barb" " barc] is equal to

If bara is perpendicular to barb and barc,|bara|=2,|barb|=3,|barc|=4 and the angle between barb and barc is (2pi)/(3) . then [bara" "barb" " barc] is equal to

The angle between a,b is 30° and barc is perpendicular to both bara and barb . if abs(bara) = 3, abs(barb)= 4, abs(barc)= 6 then abs ([bara barb barc]) =

If bara, barb are two unit perpendicular vectors then baraxx (baraxx barb) =