11." If "theta" is an acute angle such that "cos theta=(3)/(5)," then "(sin theta*tan theta-1)/(2tan^(2)theta)=

If theta is an acute angle such that cos theta=(3)/(5) then (sin theta tan theta-1)/(2tan^(2)theta)=(16)/(625) (b) (1)/(36) (c) (3)/(160) (d) (160)/(3)

If cos theta=(3)/(5), find the value of (sin theta-(1)/(tan theta))/(2tan theta)

If cos theta = (3)/(5) , then the value of (sin theta - tan theta + 1)/( 2 tan^(2) theta) is

If theta is an acute angle , cos theta = 7//25 , then tan 3 theta =

If theta is an acute angle such that sec^(2)theta=3 then the value of (tan^(2)theta-cos ec^(2)theta)/(tan^(2)theta+cos ec^(2)theta) is

If theta is an acute angle and sintheta=costheta , then find the value of 2tan^(2)theta+sin^(2)theta-1 .

If theta is an acute angle and tan theta + sec theta = 1.5 , find sin theta, tan theta and sec theta .

If theta is an acute angle and tan theta+sec theta=1.5 find sin theta,tan theta and sec theta.

If theta is an acute angle and sin theta=cos theta, find the value of 2tan^(2)theta+sin^(2)theta-1