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[154],[hline" 4.आकृति "6.36" में,"(QR)/(...

[154],[hline" 4.आकृति "6.36" में,"(QR)/(QS)=(QT)/(PR)" तथा "/_1=/_2" है। "],[" दर्राइए कि "Delta PQS sim Delta" TQR है। "]

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In the given figure (QR)/(QS)=(QT)/(PR)" and "/_1= /_2 . Show that DeltaPQS ~ DeltaTQR .

In Fig . (QR)/(QS) = (QT)/(PR)and |__ul(1)=|__ul(2) . Show that Delta PQS ~ Delta TQR

In the figure beside , (QR)/(QS)=(QT)/(PR) and /_1=/_2 . Prove that DeltaPQS~DeltaTQR .

In Fig (QR)/(QS)=(QT)/(PR)= and angle1 = angle2. show that DeltaPQS ~DeltaTQR .

In fig., (QR)/(QS)=(QT)/(PR) and angle1=angle2 . Show that trianglePQS~triangleTQR . .

In the given figure, (QT)/(PR) = (QR)/(QS) and angle 1 = angle 2 Prove that Delta PQS ~ Delta TQR .

In Fig. 6.36, (QR)/(QS)=(QT)/(PR) and angle 1=angle 2 .Show that trianglePQS~triangle TQR

In the given figure, (QT)/(PR)=(QR)/(QS) and /_1=/_2 . Prove that /_\PQS~/_\TQR .

In the given figure, (QR)/(QS)= (QT)/(PR) and angle1 = angle2 then prove that trianglePQS ~ triangleTQR.