[" One mole of aniline warmed "],[" with the mixture of "],[NaNO_(2)+HCl" .If we assume "],[100%" yield,volume of "N_(2)" gas "],[" liberated at S.T.P is "],[" 11.2L "]

One mole of phenol is warmed with sodium metal . If we assume 100% yield , volume of H_2 gas liberated at S.T.P is

Aniline reacts with mixture of NaNO_2 and HCl at 5^@ C to give

Aniline is treated with a mixture of NaNO2 and excess of HCl at low temperature.

The volume of CO_(2) gas liberated at S.T.P by heating 5 grams of pure lime stone is

2.3 gm Na is added to 6 gm of CH_(3)CO OH . The volume of H_(2) gas liberated at S.T.P.

A sample consisting fo chocolate-brown powder of PbO_(2) is allowed to react with excess of KI and iodine liberated is reacted with N_(2)H_(4) in another container. The volume of N_(2) gas liberated from this second container at STP was measured out to be 1.135 litre. Find the volume (in L) of decimolar NaOH solution required to dissolved PbO_(2) completely and convert it to Na_(2)PbO_(3) . (Assume all reactions are 100% complete).