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[1g" of a monobasic acid in "100g" of wa...

[1g" of a monobasic acid in "100g" of water lower "],[" the freezing point by "0.168^(@)" .If "0.2g" of the same "],[" acid requires "15mL" of "N/10" alkali for complete "],[" neutralisation,the degree of dissociation of the acid "],[" is "(K_(f)" for water "=1.86Kkgmol^(-1)" ) "],[[" (a) "9.8%," (b) "19.6%],[" ( "c),4.9%," (d) "1.68%]]

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1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

1.0 g of a weak monobasic acid HA in 100 g water lowers the freezing point by 0.155 K. If 0.45 g, of same acid requires 15 mL of N/5 NaOH solution for complete neutralistion then %, degree ofionization of acid is (K_f " of H"_(2)O="1.86 K kg mol"^(-1)) . a)0.2 b)0.25 c)0.4 d)0.5

1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is ( K_(f) of H_(2)O = 1.86 K kg "mol"^(-1) ):

1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is ( K_(f) of H_(2)O = 1.86 K kg "mol"^(-1) ):

1.0 g of a monobassic acid HA in 100 g water lowers the freezing point by 0.155 K. IF 0.75 g, of same acid requires 25 mL of N/5 NaOH solution for complete neutralisation then %, degree of ionization of acid is ( K_(f) of H_(2)O = 1.86 K kg "mol"^(-1) ):