In the adjacent figure, we have AC = XD, C and D are mid points of AB and XY respectively. Show that AB = XY.

In the adjacent figure ABCD is a parallelogram P and Q are the midpoints of sides AB and DC respectively. Show that PBCQ is also a parallelogram.

In Delta ABC , D and E are the mid-points of AB and AC respectively, then the area of Delta ADE is :

In the adjoining figure, D and E are the mid-points of AB and AC respectively. If DE = 4 cm , then BC is equal to :

In a parallelogram ABCD, E and F are the mid points of sides AB and CD respectively (see fig.) Show that the line segements AF and EC trisect the diagonal BD.

In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively. Show that the line segments AF and EC trisect the diagonal BD.

In adjacent figure, sides AB and AC of DeltaABC are extended to points P and Q respectively. Also, /_PBC AB.

If in a triangle AB=a,AC=b and D,E are the mid-points of AB and AC respectively, then DE is equal to

In the adjacent figure DeltaABC, D is the midpoint of BC. DE_|_AB, DF_|_AC and DE = DF . Show that DeltaBED ~= Delta CFD .

In the adjacent figure the sides AB and AC of Delta ABC are produced to points E and D respectively. If bisectors BO and CO of angleCBE and angleBCD respectively meet at point O, then prove that angleBOC = 90^(@)-(1)/(2) angleBAC .

The vertices of a Delta ABC are A (-3,2) , B (-1,-4) and C (5,2) . If M and N are the mid - points of AB and AC respectively show that 2 MN = BC .