The force applied on a body of mass 6 kg. is directly proportional to the acceleration produced in the body. Write an equation to express this observation and draw the graph of the equation.

If the work done by a body in application of a constant force is directly proportional to the distance travelled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also, send from the graph the work done when the distance travelled by the body is 2 units.

If the work done by a body in application of a constant force is directly proportional to the distance travelled by the body, express this in the form of an equation in two variables and draw the graph of the same by taking the constant force as 5 units. Also, send from the graph the work done when the distance travelled by the body is 0 units.

Calculate the force experienced on a body of mass 5 kg moves with an acceleration of 4 m//s^(2) .

A force of 100N acts on a body of mass 0.25kg for 2s . Calculate acceleration of the body and its change in momentum.

What does a constant force applied on a body produce?

A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N. Give the magnitude and direction of the acceleration of the body.

A force of 1 N acts on a body of mass 0.5 kg initially at rest. The ratio of the works done by the force in the first, second and third second is :

An auto charges 15 for first kilometer and 8 each for each subsequent kilometer. For a distance of ‘x’ km. an amount of ‘y’ is paid. Write the linear equation representing this information and draw the graph. With the help of graph find the distance travelled if the fare paid is 55? How much would have to be paid for 7 kilometers?

The kinetic energy of a body of mass 4 kg and momentum 6 N s will be

A constant force acts on a body of mass 0.9 kg at rest for 10s. If the body moves a distance of 250m, the magnitude on the force is :