In the given figure, AL || DC, E is mid point of BC. Show that `DeltaEBL ~= DeltaECD`.

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In the given figure, XY || BC , then (AX)/(BX)

Line-segment AB is parallel to another line-segment CD. O is the mid-point of AD. Show that (i) DeltaAOB ~= DeltaDOC (ii) O is also the mid-point of BC.

In the given figure, the point P bisects AB and DC. Prove that DeltaAPC ~= DeltaBPD (NCERT_KAN_MAT_IX_C07_E01_008_Q01.png" width="80%">

In the Given figure, E is any point on median AD of a triangle ABC Show that ar (ABE) = ar (ACE)

In the figure, AC = AE, AB = AD and BAD = EAC. Show that BC = DE

In the given figure AB || CD, BC || DE then find the values of x and y

In the adjacent figure, AC = AE, AB = AD and /_ BAD = /_ EAC . Show that BC = DE.

In a triangle ABC, E is the mid - point of median AD. Show that ar (BED) =1/4 ar (ABC)

In given figure, AC=AE, AB=AD and angleBAD = angleEAC . Show that BC = DE.