In quadrilateral ABCD, AB = CD, BC=AD show that `DeltaABC ~= DeltaCDA` Consider `DeltaABC and DeltaCDA`

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

In quadrilateral ACBD, AC = AD and AB bisects /_A Show that DeltaABC~= DeltaABD . What can you say about BC and BD?

In Fig , if DeltaABE angleDeltaACD , show that DeltaADE ~ DeltaABC

In the figure, AC = AE, AB = AD and BAD = EAC. Show that BC = DE

ABCD is a trapezium in which AB abs CD and AD = BC. Show that DeltaABC~=DeltaBAD

In the given Figure AB and CD are intersecting at ‘O’, OA = OB and OD = OC. Show that (i) Delta AOD ~= DeltaBOC and (ii) AD || BC .

ABCD is a trapezium in which AB||CD and AD=BC Show that angleA=angleB angleC=angleD DeltaABC approx DeltaBAD diagonal AC=diagonal BD

Find the area of a quadrilateral ABCD in which AB = 3 cm , BC = 4 cm, CD = 4 cm , DA = 5 cm and AC = 5 cm.

In the DeltaABC,AB=a,AC=c and BC=b , then

D,Eand F are respectively the mid - points of sides AB, BC and CA of DeltaABC . Find the ratio of the areas of DeltaDEF and DeltaABC.