In the adjacent figure `DeltaABC and DeltaDBC` are two triangles such that `bar(AB) = bar(BD)` and `bar(AC) = bar(CD)` . Show that `DeltaABC ~= DeltaDBC.`

DeltaABC and DeltaDBC are two isosceles triangles on thesame base BC (see figure). Show that /_ ABD = /_ ACD.

In the figure ABC and DBC are two triangles on the same base BC. If AD intersects BC at 0, show that ("Area"(DeltaABC))/("Area"(DeltaDBC))=(AO) /(DO) .

A and B are two events such that P(A) gt 0, P(B) != 1 then P(bar(A)//bar(B)) is equal to :

In the given figure, AB||DC and AD||BC show that DeltaABC ~= Delta CDA .

ABCD is a trapezium in which AB abs CD and AD = BC. Show that DeltaABC~=DeltaBAD

In the given figure, ABC and ABD are two triangles on the same base AB . If line - segment CD is bisected by AB at O, show that ar (ABC) = ar (ABD)

In the adjacent figure DeltaABC is isosceles as bar(AB) = bar(AC), bar(BA) and bar(CA) are produced to Q and P such that bar(AQ) = bar(AP) . . Show that bar(PB) = bar(QC) .

If A and B are two events such that P(A cup B) =3/4 ,P(A cap B) = 1/4 and P(bar(A)) =2/3 then P( bar(A) capB) is equal to

In the following figure, if bar(AC)=bar(BD) , then prove that bar(AB)=bar(CD) .

In the adjacent figure, AB = BC and AC = CD . Prove that : /_ BAD : /_ ADB = 3 : 1.