Home
Class 9
MATHS
ABCD is a parallelogram. AC and BD are t...

ABCD is a parallelogram. AC and BD are the diagonals intersect at O. P and Q are the points of tri section of the diagonal BD. Prove that `CQ" ||" AP` and also AC bisects PQ (see figure).

Promotional Banner

Topper's Solved these Questions

  • QUADRILATERALS

    NCERT KANNAD|Exercise EXERCISE - 8.4|6 Videos

  • QUADRILATERALS

    NCERT KANNAD|Exercise EXERCISE - 8.2|2 Videos

  • PROOFS IN MATHEMATICS

    NCERT KANNAD|Exercise EXERCISE - 15.4|15 Videos

  • REAL NUMBERS

    NCERT KANNAD|Exercise EXERCISE - 1.4|37 Videos

Similar Questions

Explore conceptually related problems

ABCD is a parallelogram, with AC, BD as diagonals. Then vec AC - vec BD =

In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively. Show that the line segments AF and EC trisect the diagonal BD.

In a rhombus ABCD, diagonals intersects at O. The sum of AC^(2) + BD^(2) are :

In a Delta ABC , let P and Q be points on AB and AC respectively such that PQ || BC . Prove that the median AD bisects PQ.

ABCD is a parallelogram whose diagonals meet at P. If O is a fixed point, then vec(OA)+vec(OB)+vec(OC)+vec(OD) equals :

If P and Q are the middle points of the sides BC and CD of the parallelogram ABCD, then AP+AQ is equal to

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure) show that (i) DeltaAPB ~= DeltaCQD (ii) AP = CQ

ABCD is a parallelogram and AP and CQ are perpendicular from vertices A and C on diagonal BD. Show that DeltaAPB approx DeltaCQD AP=CQ

The diagonal AC of a parallelogram ABCD intersects DP at the point Q, where ‘P’ is any point on side AB. Prove that CQ xx PQ = QA xx QD .

AC and BD are chord of a circle which bisect each other. Prove that (i) AC and BD are diameters.