Home
Class 9
MATHS
Prove that the median of Delta ABC divid...

Prove that the median of `Delta` ABC divides it into two triangles of equal area. .

Text Solution

Verified by Experts

The correct Answer is:
`ar(DeltaABD) = ar (DeltaACD)`
Promotional Banner

Topper's Solved these Questions

  • AREAS

    NCERT KANNAD|Exercise THINK, DISCUSS AND WRITE|3 Videos
  • AREAS

    NCERT KANNAD|Exercise EXERCISE 11.2|3 Videos
  • CIRCLES

    NCERT KANNAD|Exercise EXERCISE 12.5|3 Videos

Similar Questions

Explore conceptually related problems

You have studied in Class IX, (Chapter 9, Example 3), that a median of a triangle divides it into two triangles of equal areas. Verify this result for Delta ABC whose vertices are A(4, -6), B(3, -2) and C(5, 2).

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Prove that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.

Prove that “the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides”.

Prove that the ratio at the areas of two similar triangles is equal to the square of the ratio of their corresponding medians.

Prove that " the ratio of areas of two similar triangles is equal to the square of the ratio of their altitudes.

The vertices of a Delta ABC are A (-5,-1), B (3,-5) , C (5,2). Show that the area of the Delta ABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.

Prove that the two madians of a triangle divide each other in the ratio 2 : 1

The vertices of a Delta ABC are A(-5,-1) B(3.-5) , C-(5.2).Show that the area of the DeltaABC is four times the area of the triangle formed by joining the mid-points of the sides of the triangle ABC.