Home
Class 10
MATHS
BL and CM are medians of a triangle ABC ...

BL and CM are medians of a triangle ABC right angled at A. Prove that `4(BL^(2) + CM)^(2) = 5 BC^(2)` .

Text Solution

Verified by Experts

The correct Answer is:
`4(BL^(2) + CM)^(2) = 5 BC^(2)` .
Promotional Banner

Topper's Solved these Questions

  • SIMILAR TRIANGLES

    NCERT KANNAD|Exercise DO THIS (FILL IN THE BLANKS)|6 Videos
  • SIMILAR TRIANGLES

    NCERT KANNAD|Exercise DO THIS TRUE /FALSE|5 Videos
  • SETS

    NCERT KANNAD|Exercise Try This|11 Videos
  • TANGENTS AND SECANTS TO A CIRCLE

    NCERT KANNAD|Exercise Try this|3 Videos

Similar Questions

Explore conceptually related problems

ABC is an isosceles triangle right angled at C . Prove that AB^(2)=2AC^(2) .

In an equilateral triangle ABC, AD _|_ BC . Prove that : AB^(2) + CD^(2) = 5/4 AC^(2)

In Fig . AD is a median of a triangle ABD and AM bot BC. Prove that : AC^(2)+AB^(2)=2AD^(2)+1/2 BC^(2)

In Fig . AD is a median of a triangle ABD and AM bot BC. Prove that : AB^(2)=AD^(2)-BC.DM+((BC)/(2))^(2)

In Fig . AD is a median of a triangle ABD and AM bot BC. Prove that : AC^(2)=AD^(2)+BC. DM+((BC)/(2))^(2)

In Fig , ABC and AMP are two right triangles, right angled at B and M respectively. Prove that : (CA)/(PA)=(BC)/(MP)

In Delta ABC , BD : CD = 3 : 1 and AD _|_ BC . Prove that 2(AB^(2) - AC^(2)) = BC^(2) .

In a right-angled DeltaABC right-angled at C, P and Q are the midpoints of BC and AC. Prove that AP^(2)+BQ^(2)=5PQ^(2) .

ABC is a triangle, right angled at C. If AB=25cm and AC=7cm, find BC.