In `Delta ABC`, XY || AC and XY divides the triangle into two parts of equal area. Find the ratio of `(AX)/(XB)`.

In Delta ABC , XY || BC and XY divides the triangle into two parts of equal area. Find BX : AB . [Hint : ABC = 2 Delta AXY ]

Prove that the median of Delta ABC divides it into two triangles of equal area. .

In Delta ABC , XY || BC , (AY)/(CY) = 1/2 and AX = 4 . Find BX .

In a Delta ABC , XY || BC and XY = 1/2 BC . If the area of Delta AXY = 10 cm^(2) . Find the area of trapezium XYCB.

The sides of two triangles are in the ratio 2 : 3 . Then their areas are in the ratio :

You have studied in Class IX, (Chapter 9, Example 3), that a median of a triangle divides it into two triangles of equal areas. Verify this result for Delta ABC whose vertices are A(4, -6), B(3, -2) and C(5, 2).

Prove that the two madians of a triangle divide each other in the ratio 2 : 1

Sides of two similar triangles are in the ratio 4 : 9 Areas of these triangles are in the ratio

In Delta ABC , D and E are the mid-points of AB and AC respectively, then the area of Delta ADE is :

Find the ratio between areas of Delta AOB and Delta COD , if AB = 3 CD