If `DeltaABC~DeltaDEF, BC=3cm, EF=4cm`, and Area of `DeltaABC=54cm^(2)`, then Area of `Delta DEF` is

If Delta ABC ~ Delta DEF, BC = 3cm, EF = 4cm, and Area of Delta ABC = 54 cm^(2) , then Area of Delta DEF is

Delta ABC - Delta DEF , Area of Delta ABC = 64 cm^(2) and area of Delta DEF = 121 cm^(2) . If EF = 15.4 cm , Find BC.

DeltaABC~DeltaDEF . If AB = 4 cm, AC = 3.5 cm, BC = 3 cm, and EF = 6 cm, the perimeter of DeltaDEF is

AX an BY are perpendiculars to segment XY . If AO = 5 cm , BO = 7 cm and Area of Delta AOX= 150 cm^2 , find the area of Delta BOY .

DeltaABC~DeltaDEF . If area (DeltaABC)=2.89m^(2) , area (DeltaDEF)=2.25m^(2) , and AB = 1.5 m, find DE.

In DeltaABC , XY || BC and XY=(1)/(2)BC . If the area of DeltaAXY=10cm^(2) , find the area of trapezium XYCB.

If Delta ABC and Delta DEF are similar and 2AB = DE , BC = 8 cm , then calculate EF.