For any sets A and B, show that
`P ( A ∩ B ) = P ( A ) ∩ P ( B )`.

Show that for any sets A and B, A = ( A ∩ B ) ∪ ( A – B ) and A ∪ ( B – A ) = ( A ∪ B )

Is it true that for any sets A and B, P ( A ) ∪ P ( B ) = P ( A ∪ B ) ? Justify your answer.

For any two events A and B , P (A cap B) is :

Assume that P ( A ) = P ( B ) . Show that A = B

Given two independent events A and B such that P(A) = 0 . 3, P (B) = 0 . 6 . Find P(A and B)

Given two independent events A and B such that P(A) = 0 . 3, P (B) = 0 . 6 . Find P(A or B)

Given two independent events A and B such that P(A) = 0 . 3, P (B) = 0 . 6 . Find P(A and not B)

It is given that events A and B are such that : P(A) = 1/4 ,P (A//B) =1/2 and P (B//A) =2/3 . Then P(B) is :

Given that the event A and B are such that P(A) = 1//2, P (Acup B) = 3 //5 and P(B) = P . Find p, if they are mutually exclusive

If A, B, C are three events associated with a random experiment, prove that P(A uu B uu C) = P(A) + P(B) + P(C) - P(A nn B) - P(A nn C) P(B nn C) + P (A nn B nn C)