If the first and the `n^("th")` term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that `P^2 = (ab)^n`.

Similar Questions

Explore conceptually related problems

The first and the n^(th) elements of a G.P are respectively a and b and P is the product of n elements, then P^(2)=

The fourth seventh and tenth terms of a G.P. are p,q,r respectively, then :

If the 2^(nd) and 5^(th) terms of a G.P are 24 and 3 respectively , then the sum of 1^(st) six terms is _______

The 4^(th) and 9^(th) terms of a G.P. Are 54 and 13122 respectively .Find the 6^(th) term .

If the 2^(nd) and 5^(th) terms of G.P. are 24 and 3 respectively then the sum of 1^(st) six terms is :

The 5th ,8th , 11th , terms of a G.P. are p,q and s, respectively .Show that q^(2) =ps

The 7th and 13th terms of an A.P. are 34 and 64 respectively, 1 Then its first term difference are:

The first term of a G.P is 3 and 6^(th) element is (3)/(32), then if P is the product of 6 elements, then P^(2)=

If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in GP.

If the 4th , 7 th and 10th term of a G.P. be a,b,c respectively, then the relation between a,b,c is :