If a, b, c are in A.P., b, c, d are in G.P. and `1/c,1/d,1/e` are in A.P. prove that a,c,e are in GP.

a, b, c are in A.P, b, c, d are in G.P and c, d, e are in H.P, then a, c, e are in

If a,b,c,d are in H.P., then :

If a,b,c are in AP and b,c,d be in HP, then

If a, b, c are in A.P., a, x, b are in G.P., and b, y, c are in G.P., then (x, y) lies on :

If a,b,c are in A.P. and a,mb,c are in G.P. , then a, m^(2)b, are in :

If a,b,c are in HP,b,c,d are in GP and c,d,e are in AP, than show that e=(ab^(2))/(2a-b)^(2) .

Given a,b,c are in A.P.,b,c,d are in G.P and c,d,e are in H.P .If a=2 and e=18 , then the sum of all possible values of c is ________.

If a(1/b+1/c),b(1/c+1/a),c(1/a+1/b) are in A.P., prove that a,b,c are in A.P.

If a,b,c are in A.P. and a^(2) , b^(2) , c^(2) are in H.P. , then :

If a, b, c are in A.P., p, q, r are in HP and ap, bq, cr are in GP, then (P)/(r)+(r)/(P) is equal to