In fig 10.9 , time and distance graph of a linear motion is given.
Two positions of time and distance are recorder as, when `T = 0, D = 2` and when `T = 3, D = 8 ` . Using the concept of slope, find law of motion , i.e., how distance depends upon time.

A car starts from a point P at time t = 0 seconds and stops at point Q. The distance x, in metres, covered by it, in t seconds is given by x = t^(2)(2-t/3) . Find the time taken by it to reach Q and also find the distance between P and Q.

The distance s feet travelled by a particle in time t second is given by s = t^3 - 6t^2 - 4t -8 . It acceleration vanishes at time t =

A car starts from a point P at time t = 0 seconds and stops at point Q. The distance x, in metres, covered by it, in t seconds is given by x=t^(2) (2-(t)/(3)) Find the time taken by it to reach Q and also find distance between P and Q.

Figure here gives the speed-time graph for a body. The distance travelled between I = 1.0 second and t = 7.0 second is nearest to:

The speed time graph of a particle moving along a fixed direction is as shown in the figure. Obtain the distance travelled by the particle from, (a) t = 0 to 10s (b) t= 2s to 6s (c) What is the average speed of the particle over the intervals in (a) and (b)?

The distance s feet travelled by a particle in time t seconds is given by s = t^(3) - 6 t^(2) - 4t - 8 . Its acceleration vanishes at time t =