If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that `1/p^(2) = 1/a^(2) + 1/b^(2)`.

If p is the length of the perpendicular from the origin on the line whose intercepts on the axes are a and b, then

If p is the length of perpendicular from origin to the line whose intercepts on the axes are 'a' and 'b' then prove that (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2)) .

The tangent of angle between the lines whose intercepts on the axes are a,-b and b,-a respectively, is

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

Derive the expression for the length of the perpendicular drawn from the point (x_1,y_1) yo the line ax + by + c=0

Product of lengths of perpendiculars drawn from the foci on any tangent to the hyperbola x^2/a^2-y^2/b^2=1 is :

ABC is a right triangle right angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB. Prove that (i) pc = ab (ii) (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2)) .

Find the product of the perpendiculars drawn from the point (x_1,y_1) on the lines ax^2+2hxy+by^2=0

If p_1p_2,p_3 are the lengths of altitudes of a triangle from the vertices A, B, C and Delta the area fo the triangle the 1/p_1 + 1/p_2 - 1/p_3 =

Prove that the product of the lengths of the perpendiculars drawn from the points (sqrt(a^(2) - b^(2)) , 0) " and " (- sqrt(a^(2) - b^(2)), 0) to the line x/a cos theta + y/b sin theta = 1 " is " b^(2) .