If `f(x) = ((4x + 3 ))/( ( 6x - 4 )), x ne 2/3,` show that fof `(x) =x,` for all `x ne 2/3.` What is the inverse of f ?

if f(x) = 1/(1-x) (x ne 1), {f[f(x)]} is

If f(x) = {((x^(5)-32)/(x-2), x ne 2),(k, x =2):} is continuous at x = 2, then k =

If f(x) = {(1/(1+e^(1/x)), x ne 0),(0, x= 0):} then f(x) is

If f(x) = 2x^3 + 3x^2 + 11x + 6 , then f(1) is :

If f : R to R be given by f (x) = (3 -x ^(3)) ^(1/3), then fof (x) is

Verify whether the function f : N to Y defined by f(x) = 4x + 3 , where Y = {y : y = 4x + 3, x in N} is invertible or not. Write the inverse of f(x) if exists.

If f(x) = {{:( (x^(2) - (a + 2) x + a)/(x - 2) " , " x ne 2) , (2 " " " , " x = 2):} is continuous at x = 2 , then the value of a is

In the interval (-3,3) the function f(x) = x/3 + 3/x, x ne 0 is