[9" balls are to be placed in "9],[" boxes; and "5" of the balls cannot "],[" fit into "3" small boxes.The "],[" number of ways of arranging "],[" one ball in each of the boxes is "],[0" "18720],[0" ,"18270],[" 0"17280],[" 0."12780]

9 balls are to placed in 9 boxes : and 5 of the balls cannot fit into 3 small boxes the number of ways of arranging one ball in each of the boxes is

7balls (distinct) are to be placed in 7 boxes (distinct) and 4 of the balls can not fit into 2 small boxes.The number of ways of arranging one ball in each of the boxes is X .Let P be the probability of selected divisor in the list of divisors of X is in the Form of 4n+1 ,then find 6P (where n in N)

Five balls are to be placed in three boxes in how many diff. ways can be placed the balls so that no box remain empty if .

There are 9 objects and 9 boxes. Out of 9 objects, 5 cannot fit in three small boxes. How many arrangements can be made such that each object can be put in one box only.

5 balls are to be placed into 3 boxes such that no box remains empty The number of ways in which this can be done.

There are 5 different coloured balls and 5 boxes of the same colour as that of balls the number of ways that exactly two balls will go to its same coloured boxes is