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If A=[(alpha, beta),(gamma, -alpha)] is ...

If `A=[(alpha, beta),(gamma, -alpha)]` is such that `A^(2)=I`, then

A

`1+alpha^(2)+beta gamma=0`

B

`1-alpha^(2)+beta gamma=0`

C

`1-alpha^(2)-beta gamma=0`

D

`1+alpha^(2)-beta gamma=0`

Text Solution

Verified by Experts

The correct Answer is:
C
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