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int("sec"^(2)x)/("cosec"^(2)x) dx....

`int("sec"^(2)x)/("cosec"^(2)x) dx`.

Text Solution

Verified by Experts

The correct Answer is:
`tanx-x+C`
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Knowledge Check

  • (1-sec^(2)A)/(cosec^(2)A-1) equals:

    A
    `-sec^(2)A`
    B
    `tan^(4)A`
    C
    `-tan^(4)A`
    D
    1

  • int_(pi/4)^(pi/2) cosec^(2)x dx =

    A
    0
    B
    4
    C
    -1
    D
    1

  • sec (cosec^(-1) x)=

    A
    `cosec(sec ^(-1) x)`
    B
    `cot x`
    C
    `pi`
    D
    none of these

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    If f(x) = int (x^(2)+sin^(2)x)/(1+x^(2)) sec^(2)x dx and f(0) = 0, then f(1) =

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