(dy)/(dx) = y tan x, y = 1 when x = 0...

`(dy)/(dx) = y tan x, y = 1` when x = 0

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The correct Answer is:

`y = sec x`

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If y = x tan y, then dy/dx =

A

`(x tan y)/(x-x^(2)-y^(2))`

B

`y/(x-x^(2)-y^(2))`

C

(tan y)/(y-x)

D

none of these

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