X-rays of wavelength `lambda` fall on photosenstive surface, emitting electrons. Assuming that the work function of the surface can be neglected, prove that the de-broglie wavelength of electrons emitted will be `sqrt((hlambda)/(2mc))`.

X-rays of wavelength 'lambda' fall on a photosensitive surface emitting electrons. Assuming that the work-function of the surface can be neglected, prove that the de Broglie wavelength of electrons emitted will be sqrt(( h lambda)/(2mc))

X-rays of wavelength lambda fall on an phtot senstive surface,emitting electrons.Assuming that the work function of the surface can be netglected,prove that the de-Broglie wavelength of electrons emited will be sqrt(h lambda//(2 m c)) .

X-rays of wavelength lambda fall on photosensitive-surface emitting electrons. Assuming that the work function of the surface can be neglected, prove that the de-Bfoglie wave-length of eleectrons emitted will be root ((hlambda)/(2mc)) .What is threshold frequency?

X-ray fall on a photosenstive surface to cause photoelectric emission. Assuming that the work function of the surface can be neglected, find the relation between the de -Broglie wavelength (lambda) of the electrons emitted to the energy (E_v) of the incident photons. Draw the nature of the graph for lambda as a function of E_v .

X-rays fall on a photosensitive surface to cause photoelectric emission. Assuming that the work function of the surface can be neglected, find the relation between the de-Broglie wavelength ( lambda ) of the electrons emitted to the energy ( E_(v) ) of the incident photons. Draw the nature of the graph for lambda as a function of E_(v) .

If an em wave of wavelength lambda is incident on a photosenstive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength lambda_1 , prove that lambda=((2mc)/h)lambda_1^2