Home
Class 11
PHYSICS
Stopping distance of vehicles : When bra...

Stopping distance of vehicles : When brakes are applied to a moving vehicle, the distance it travels before stopping is called stopping distance. It is an important factor for road safety and depends on the initial velocity `(upsilon_(0))` and the braking capacity, or deceleration, `-a` that is caused by the braking. Derive an expression for stopping distance of a vehicle in terms of `upsilon_(0)` and a.

Text Solution

Verified by Experts

Let the distance travelled by the vehicle before it stops be `d_(s)`. Then, using equation of motion `upsilon^(2)=upsilon_(0)^(2)+2 ax`, and noting that `upsilon = 0`, we have the stopping distance
`d_(s)=(-upsilon_(0)^(2))/(2a)`
Thus, the stopping distance is proportional to the square of the initial velocity. Doubling the initial velocity increases the stopping distance by a factor of 4 (for the same deceleration). For the car of a particular make, the braking distance was found to be 10 m, 20 m, 34 m and 50 m corresponding to velocities of 11, 15, 20 and 25 m/s which are nearly consistent with the above formula. Stopping distance is an important factor considered in setting speed limits, for example, in school zones.
Promotional Banner

Similar Questions

Explore conceptually related problems

A bus is moving with the initial velocity of 'u' m/s. After applying the breaks, its retardation is 0.5 m/ s^(2) and it stoped after 12s. Find the initial velocity (u) and distance travel by the bus after applying the breaks.

A car moving at a speed v is stopped in a certain distance when the brakes produce a deceleration a. If the speed of car was nv , what must be the decceleration of the car to stop it in the same distance and in the same time?

The distance travelled by a motor car in t seconds after the brakes are applied is s feet where s = 22t -12t^(2) . The distance travelled by the car before it stop is

At a distance L= 400m away from the signal light,brakes are applied to a locomotive moving with a velocity, u = 54 km/h.Determine the position of rest of the locomotive relative to the signal light after 1 min of the application of the brakes if its acceleration a = - 0.3 m/ s^(2)

A car is moving at 72kmph . Brakes are suddenly applied causing all the tyres to skid. How far will the car move before coming to a stop (given g=9.8ms^(-2) and mu=0.2 )?

A car moving with a velocity of 20 ms^(-1) is stopped in a distance of 40 m. If the same car is travelling at double the velocity, the distance travelled by it for same retardation is

A car moving with a speed of 50 km/h, can be stopped by brakes after at least 6 m. If the same car is moving at a speed of 100 km/h, the minimum stopping distance is :

An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is moving twice as fast i.e. 120 km/h, the stopping distance will be

A car moving with a speed of 40 km/h can be stopped by applying brakes after at least 2 m. If the same car is moving with 80 km/h, what is the least stopping distance ?