Home
Class 11
PHYSICS
A bullet of mass 0.04 kg moving with a s...

A bullet of mass 0.04 kg moving with a speed of `90 m s^(-1)` enters a heavy wooden block and is stopped after a distance of 60 cm. What is the average resistive force exerted by the block on the bullet?

Text Solution

Verified by Experts

The retardation ‘a’ of the bullet (assumed constant) is given by
`a = ( -u^2)/(2s) = (-90 xx 90)/(2 xx 0.6) ms^(-2) = - 6750 ms^(-2)`
The retarding force, by the second law of motion, is
`= 0.04 kg xx 6750 m s^(-2) = 270 N `
The actual resistive force, and therefore, retardation of the bullet may not be uniform. The answer therefore, only indicates the average resistive force.
Promotional Banner

Similar Questions

Explore conceptually related problems

A bullet of mass 10 g travelling horizontally with a velocity of 150 m s^(-1) strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on he bullet.

A stone of 1 kg its thrown with a velocity of 20 m s^(-1) acroos the frozen surface of a lake and comes to rest after travelling a distance of 50 m. What is the force of friction between the stone and the ice ?

A 3 kg ball strikes a heavy rigid wall with a speed of 10 ms at an angle of 60°. It gets reflected with the wall is for 0.20 s, what is the average force exerted on the ball by the wall ?

A block of mass 0.50 kg is moving with speed of 2.00 ms^(-1) on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collisions is

A bullet of mass 0.012 kg and horizontal speed 70ms^(-1) strikes a block of wood of mass 0.4 kg and instantly comes to rest with respect to the block. The block is suspended from the ceiling by means of thin wires. Calculate the height to which the block rises. Estimate the loss in kinetic energy.

A wooden block of mass 2 kg rests on a soft horizontal floor. When an iron cylinder of mass 25 kg is placed on top of the block, the floor yields steadily and the block and the cylinder together go down with an acceleration of 0.1 m s^(-2) . What is the action of the block on the floor (a) before and (b) after the floor yields ? Take g = 10 m s^(-2) . Identify the action-reaction pairs in the problem.

A body of mass of 2 kg moving with velocity 4 ms^( -1) horizontally stops after 2 s. If the body is to be kept in motion at the same surface with 4 ms^(-1) force needed is :

A hammer of mass 500 g, moving at 50ms^(-1) strikes a nail. The nail stops the hammer in a very short time of 0.01s. what is the force of the nail on the hammer.