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A mild steel wire of length 1.0 m and cr...

A mild steel wire of length 1.0 m and cross - sectional area `0.50xx10^(-2)" cm"^(2)` is stretched, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid - point of the wire. Calculate the depression at the mid point.

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The correct Answer is:
Approximately 0.01 m
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Knowledge Check

  • A wire of cross-section A is stretched horizontally between two clamps located 21 metre apart. A weight W kg is suspended from the mid point of the wire. If the mid point sags vertically through a distance x < l the strain produced is :

    A
    `(2x^(2))/(l^(2))`
    B
    `(x^(2))/(l^(2))`
    C
    `(x^(2))/(2l^(2))`
    D
    None of these.

  • The specific resistance of a wire of length 1m, area of cross-section 0.5 m^(2) , is 25 micro-ohm cm. The resistance of the wire is

    A
    `2 xx 10^(-6)` ohms
    B
    `3 xx 10^(-6)` ohms
    C
    `6 xx 10^(-5)` ohms
    D
    `5 xx 10^(-5)` ohms

  • A current of 5 A is passing through a metallic wire of cross- sectional area 4 xx 10^(-6) m^(2) . If the density of charge carries of the wire is 5 xx 10^(26) m^(-3) , the drift velocity of the electrons will be

    A
    `1 xx 10^(2) ms^(-1)`
    B
    `1.56 xx 10^(-2) ms^(-1)`
    C
    `1.56 xx 10^(-3) ms^(-1)`
    D
    `1 xx 10^(-2) ms^(-1)`

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