Six lead - acid type of secondary celJs each of emf 2.0V and internal resistance `0.015Omega` are joined in series to provide supply to a resistance of `8.5Omega`. What is the current drawn from the supply and its terminal voltage?

(a) Six lead acid type of secondary cells each of 2.0 V and internal resistance 0.015 omega are joined in series to provide a supply resistance of 8.5 omega what are the current drawn from the supply and its terminal voltage (b) A secondary cell after long use has an e.m of 1.9 V and largic internal resistance of 380 omega what maximum current can be draw from the cell ? Could the cell drive the starting motor of a car ?

Five cells each of internal resistance 0.2 Omega and e.m.f. 2V are connected in series with a resistance of 4 Omega . The current through the external resistance is :

A battery having emf 4 V and internal resistance 0.5 Omega is connected with a resistance of 4.5 Omega . The voltage at the terminals of the battery now is

A storage battery of emf 8.0V and internal resistance 0.5Omega is being charged by a 120 V de supply using a series resistor of 15.5Omega. What is the terminal voltage of the battery during charging? What is the purpose of having a series resistor in the charging circuit ?

In the electric circuit shown , each cell has an e.m.f. of 2V and internal resistance of 1 Omega . The external resistance is 2 Omega . The value of the current I is (in A).

If the combination is connected to a battery of emf 20 v and negligible internal resistance determine the current through each resistor , and the total current drawn from the battery .

Three similar cells, each of emf 2 V and internal resistance r Omega send the same current through an external resistance of 2 Omega when connected in series or in parallel. The strength of the current flowing through the external resistance is (A)