Home
Class 12
PHYSICS
Light of wavelength 488 nm is produced b...

Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.

Text Solution

Verified by Experts

`2.16eV=3.46xx10^(-19)J`
Promotional Banner

Similar Questions

Explore conceptually related problems

When light of wavelength 300 nm falls on a photoelectric emitter, photoelectrons are liberated. For another emitter, light of wavelength 600 nm is sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

The wavelength of light from the spectral emission line of sodium is 589 nm. Find the kinetic energy at which (a) an electron, and (b) a neutron, would have the same de Broglie wavelength.

Light emitted during the de excitation of electron from n = 3 to n = 2, when incident on a metal, photoelectrons are just emitted from that metal. In which of the following deexcitations photoelectric effect is not possible ?

Calculate the longest wavelength of incident light on platinum for which photo electrons are just emitted from platinum (work function for platinum = 6.2 eV).

Ultraviolet light of wavelength 2271 Å from a 100 W mercury source irradiates a photo-cell made of molybdenum metal. If the stopping potential is -1.3 V , estimate the work function of the metal. How would the photo-cell respond to a high intensity (~10^(5) W m^(2)) red light of wavelength 6328 Å produced by a He-Ne laser ?