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A monoenergetic electron beam with elect...

A monoenergetic electron beam with electron speed of `5.20xx10^(6) ms^(-1)` is subject to a magnetic field of `1.30xx10^(-4)T`normal to the beam velocity. What is the radius of the circle traced by the beam? Given `e//m = 1.76 xx 10^(11) kg^(-1)`.

Text Solution

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(a) 22.7 cm
(b) No. As explained above, a 20 MeV electron moves at relativistic speed. Consequently, the non-relativistic formula `R = (m_(0) v//e B)` is not valid. The relativistic formula is
`R=p//eB=mv//eB or R=m_(0)v//(eBsqrt(1-v^(2)//c^(2)))`
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