Home
Class 12
PHYSICS
Under certain circumstances, a nucleus c...

Under certain circumstances, a nucleus can decay by emitting a particle more massive than an a-particle. Consider the following decay processes:
`""_(88)^(223)Ra to ""(82)^(209)Pb + ""_(6)^(14)C`.
`""_(88)^(223)Ra to ""_(86)^(219)Rn + ""_(2)^(4)He`
Calculate the Q-values for these decays and determine that both are energetically allowed.

Text Solution

Verified by Experts

For `""_(6)^(14)C` emission
`Q=[m(N)(""_(88)^(223)Ra)-m(N)(""_(82)^(209)Pb)-m(N)(""_(6)^(14)C)]c^(2)`
`=[m(""_(88)^(223)Ra)-m(""_(82)^(209)Pb)-m(""_(6)^(14)C)]c^(2)=31.85MeV`
For `""_(2)^(4)He" emission, "Q-[m(""_(86)^(223)Ra)-m(""_(86)^(219)Rn)-m(""_(2)^(4)He)]c^(2)=5.98MeV`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the Q-value and the kinetic energy of the emitted a-particle in the a-decay of (a) ""_(88)^(226)Ra and (b) (86)^(220)Rn . Given m (""_(88)^(226)Ra) = 226.02540 u, " " m (""_(86)^(222)Rn) = 222.01750 u , m (""_(86)^(220)Rn) = 220.01137u, " " m(""_(84)^(216) Po) = 216.00186u .