A line is of length 10 unit and one end is at (2, -3). If the abscissa of the other end is 10. Then its ordinate is

A line is of the length 10 units and one end is at (2,-3). If the abscissa of the other end is 10, then find its ordinate.

A line is of length 10 units and one of its ends is (-2, 3) . If the ordinate of the other end is 9, prove that the abscissa of the other end is 6 or -10

A line is of length 10 units and one of its ends is (-2, 3) . If the ordinate of the other end is 9, prove that the abscissa of the other end is 6 or -10

The length of a line segment is 10 units . If the coordinates of its one end point are (2,-3) and the abscissa of the other end point is 10, then its ordinate is . . . . .

A line of length 10 units has one end at the point (-3,2). If the ordinate of the other end is 10, show that the abscissa will be 3 or -9.

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3)dot If the abscissa of the other end is 10, find the ordinate of the other end.

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3) . If the abscissa of the other end is 10, find the ordinate of the other end.

The length of a line segment is of 10 units and the coordinates of one end-point are (2,-3). If the abscissa of the other end is 10, find the ordinate of the other end.

A line AB is of length 5. A is the point (2,-3) .If the abscissa of the point B is 5" prove that the ordinate of B is 1 or -7

The length of a line segment is sqrt(29) units. If one end is at (-3,5) and the ordinate of the other end is 7 , show that the absciss is either 2 or - 8 .