दो समतलों `2x+3y +4z=4 ` और `4x+6y +8z=12` के बीच की दुरी है :

Find the angle between the planes : (i) 3 x - 6y - 2z = 7 " " 2x + y - 2z = 5 (ii) 4 x + 8y + z = 8 " " and y + z = 4 (iii) 2 x - y + z =6 " " and x + y + 2z = 7 .

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is(A) 2 units (B) 4 units (C) 8 units (D) 2/(sqrt(29)) units

If x : y : z = 3:4:5 and x + y + z = 96, then what is the value of z ? यदि x : y : z = 3:4:5 और x + y + z= 96 है, तो z का मान कितना है?

Distance between the planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is :

Distance between two planes : 2x + 3y + 4z = 5 and 4x + 6y + 8z = 12 is :

Add : 8x - 3y + 7z, -4x + 5y - 4z, -x - y - 2z

Distance between two planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 16 is :

If x+y+z=19, x^2+y^2+z^2=133 and xz=y^2 , then the difference between z and x is : यदि x^2+y^2+z^2=133 तथा xz=y^2 है, तो z और x के बीच क्या अंतर है ?

If p_1,P_2,P_3 denot the distances of the plane 2x-3y+4z +2 = 0 from the planes 2x-3y + 4z + 6 = 0, 4x-6y+8z +3 = 0 and 2x -3y + 4z -6 = 0 repectively then , .......... Is not true.