The velocity of a particle is given by `v=v_(0) sin omegat`, where `v_(0)` is constant and `omega=2pi//T`. Find the average velocity in time interval `t=0 `to `t=T//2.`

The velocity of a particle moving along the xaxis is given by v=v_(0)+lambdax , where v_(0) and lambda are constant. Find the velocity in terms of t.

A particle move with a velocity v=alpha t^(3) along a straight line.The average velocity in time interval t=0 to t=T is

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

The velocity of an object moving rectilinearly is given as a function of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velocity if particle between t=0 to t=2 seconds is

The position x of a particle at time t is given by x=(V_(0))/(a)(1-e^(-at)) , where V_(0) is constant and a gt 0 . The dimensions of V_(0) and a are

The position x of a particle at time t is given by : x=(v_(0))/(a)(1-e^(-at)) where v_(0) is a constant and a>0. The dimensional formula of v_(0) and a is :

The velocity of an object moving rectillinearly is given as a functiion of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velociy if particle between t=0 to t=2 seconds is

A particle executes simple harmonic motion about x=0 along x-axis. The position of the particle at an instant is given by x= ( 5 cm) sin pi t . Find the average velocity and average acceleration for a time interval 0-0.5 s . Hint : Average velocity =( x_(2)- x_(1))/(t_(2)-t_(1)) x_(1) = 5 sin 0 x_(2) = 5 sin ( pi xx 0.5) t_(2) - t_(1) = 0.5 Average acceleration = ( v_(2) - v_(1))/( t_(2) - t_(1)) v=(dx)/(dt) = 5 pi cos pit implies a _(av) = ( 5 pi cos ( pi xx 0.5) -5 pi cos theta)/(0.5)