If `bar(a), bar(b), bar(c)` form a left handed orthogonal system and `bar(a)*bar(a)=4, bar(b)*bar(b)=9, bar(c)*bar(c)=16` then `[bar(a) bar(b) bar(c)]` =

If bar(a)xxbar(b)=bar(c) and bar(b)xxbar(c)=bar(a), then

If bar(a)+bar(b)+bar(c)=bar(0) then bar(a)timesbar(b)=

If [bar(a)+2bar(b)2bar(b)+bar(c)5bar(c)+bar(a)]=k[bar(a)bar(b)bar(c)]

Show that (bar(a)+bar(b)) . [(bar(b)+bar(c)) xx (bar(c )+bar(a))] = 2[bar(a)bar(b)bar(c )] .

If |bar(a)|=|bar(b)|=|bar(c)|=2 and bar(a).bar(b)=bar(b).bar(c)=bar(c).bar(a)=2 then [bar(a) bar(b) bar(c)] equal to

If bar(a),bar(b) and bar(c) are perpendicular,bar(c)+bar(a),bar(b)+bar(c) and bar(a)+bar(b)+ respectively and if |bar(a)+bar(b)|=6,|bar(b)+bar(c)|=8 and |bar(c)+bar(a)|=10 then |bar(a)+bar(b)+bar(c)| is equal to

if bar(a),bar(b),bar(c) are any three vectors then prove that [bar(a),bar(b)+bar(c),bar(a)+bar(b)+bar(c)]=0

If bar(a),bar(b) and bar( c ) are perpendicualr to bar(b)+bar( c ),bar( c )+bar(a) and bar(a)+bar(b) respectively and |bar(a)+bar(b)|=6,|bar(b)+bar( c )|=8 and |bar( c )+bar(a)|=10 then |bar(a)+bar(b)+bar( c )| =……………….

(bar(a)+2bar(b)-bar(c))*(bar(a)-bar(b))xx(bar(a)-bar(bar(c)))=

The points 2bar(a)+3bar(b)+bar(c), bar(a)+bar(b), 6bar(a)+11bar(b)+5bar(c) are