Missing term in the following table is `{:(x " " : 0 , 1 , 2 , 3 ,4) , ( y = f(x) : 1,3,9, ? , 81):}`

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Find the value of (( x -y )^3 + ( y - z )^3 + ( z - x )^3 )/ (9 ( x - y )( y - z ) ( z - x )) 1 . 0 2 . 1/9 3 . 1/3 4. 1

Solve : 3(81)^(x) + 3 = 9^(x + 1) + 9^(x) .

Find the sum of indicated number of terms of each of the following A.P.'s (i) 5,2,-1,-4,-7,…………., n terms (ii) -1,1/4,3/2,…………..,81 terms (iii) 2,4,6,…………,100 terms (iv) -0.5,-1.0,-1.5,……………, 10 terms ; 50 terms (v) x+y,x-y,x-3y,..................22 terms

Find f^(-1) if it exists: f: A->B where A={1,\ 3,\ 5,\ 7,\ 9}; B= {0,\ 1,\ 9,\ 25 ,\ 49 ,\ 81} and f(x)=x^2 .

Find f^(-1) if it exists: f: A->B where A={1,\ 3,\ 5,\ 7,\ 9}; B= {0,\ 1,\ 9,\ 25 ,\ 49 ,\ 81} and f(x)=x^2 .

If X = { 1 , 2 , 3} and Y = {0 , 1} and f : X to Y defined by f = { (1 , 1) , (2 , 1) , (3, 0) } , then f is

If f(x)=x^3+4x^2-x , find f(A) , where A=[(0 ,1, 2 ),(2,-3 ,0),( 1,-1 ,0)] .

If f'(x)=1/(3-x)^2 , the equation of the tangent line to f(x) at (0, 1/3) is y=x/9+1/3 .