`int_(-2)^2min(x-[x],-x-[-x])dx` equals, where [ x ] represents greatest integer less than or equal to x.

int_(-2)^(2) min(x-[x],-x-[x])dx equals, where [x] represents greates integer less than or equal to x.

If f(x)=|x-1|-[x] , where [x] is the greatest integer less than or equal to x, then

If f(x)=|x-1|-[x] , where [x] is the greatest integer less than or equal to x, then

int_(0)^(15/2)[x-1]dx= where [x] denotes the greatest integer less than or equal to x

Consider the integral I=int_(0)^(10)([x]e^([x]))/(e^(x-1))dx , where [x] denotes the greatest integer less than or equal to x. Then the value of I is equal to :

If f(x)=|x-1|-[x] (where [x] is greatest integer less than or equal to x ) then.

If [.] represent greatest integer less than or equal to x, then int_0^2 (x+[x-2[x]])^([2x]) dx=

If I=int_(-1)^(1) {[x^(2)]+log((2+x)/(2-x))}dx where [x] denotes the greatest integer less than or equal to x, the I equals

The domain of definition of the function f(x)=tan((pi)/([x+2])) , is where [] represents greatest integer function less than or equal to x.