" Ex.(1) "(x^(2)+4x+4)-:(x+2)

If f(x)=(1)/(x^(2)+4x+4)-(4)/(x^(4)+4x^(3)+4x^(2))+(4)/(x^(3)+2x^(2)) the f (1/2) is equal to

int ((x ^ (-6) -64) / (4 + 2x ^ (-1) + x ^ (-2)) * (x ^ (2)) / (4-4x ^ (-1) + x ^ (-2))-(4x ^ (2) (2x + 1)) / (1-2x)) dx

If f(x) {:(=(x^(2)-4x+3)/(x^(2)-1)", ..."x!=1 ),( =2", ..."x=1):} then :

Evaluate: lim_(x rarr 1) (2x^(2)+4x+4)/(2x-1) .

If y=(1+(1)/(x^(2)))/(1-(1)/(x^(2)))backslash then (dy)/(dx)=-(4x)/((x^(2)-1)^(2))b-(4x)/(x^(2)-1) c.(1-x^(2))/(4x)d*(4x)/(x^(2)-1)

If y=(1+1/(x^2))/(1-1/(x^2)) , then (dy)/(dx) = a. -(4x)/((x^2-1)^2) b. -(4x)/(x^2-1) c. (1-x^2)/(4x) d. (4x)/(x^2-1)

If 2x - (1)/(2x) =4 , find : (i) 4x^(2) + (1)/( 4x^2)