यदि `f(x) = {{:((x^(2)-9)/(x-3), x ne 3), (k, x=3):}`, बिंदु x=3 सतत हैं तो k ज्ञात कीजिए|

f(x)={{:((x^(2)-9)/(x-3)",when "xne3),(k", when "x=3):} at x = 3

Examine the continuity of f(x) = {:{((x^2-9)/(x-3), x ne 3),(6,x=3):} at x = 3

Determine the constant k, so that the function f(x) = {{:((x^2- 9)/(x -3)"," ,x != 3),(k",", x = 3):} is continuous at x=3.

If f(x) = {((x^2-9)/(x-3),,x,ne,3),(m,,x,=,3):} is continuous at x = 3 , then value of m is :

यदि फलन f(x)={{:(,((4^(x)-1)^(3))/(sin(x//4)log(1+x^(2)//3)),x ne 0),(,k,x=0):} , x=0 , पर सतत है तब k=

If the function f(x)={{:((x ^(2) -9)/(x-3), "when" x ne3),(2x+a, "when" x=3):} is such that lim _(x to3) f(x) =f(3), then the value of a is-

Let f (x = {{: ((x^(2) - 4x + 3)/(x^(2) + 2x - 3), x ne 1),(k, x = 1):} If f (x) is continuous at x= 1, then the value of k will be