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Let f(x) = log(1+x^2) and A be a constan...

Let `f(x) = log(1+x^2)` and `A` be a constant such that `|f(x)-f(y)|/|x-y| <= А` for all x,y real and `x != y`. Then the least possible value of A is (A) equal to 1(B) bigger than 1 but less than 2 (C) bigger than 0 but less than 1(D) bigger than 2

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